The Modern Mechanic; A Scientific and Calculator, Comprising Rules and Tables in the Various Departments of Mechanical Skill and Labor

The Modern Mechanic; A Scientific and Calculator, Comprising Rules and Tables in the Various Departments of Mechanical Skill and Labor

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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1861 edition. Excerpt: ...the same as it would acquire by falling through half the radius by the constant action of the centripetal force. From these facts the following rules for central forces are derived. _ veloc. of rev. body3 X weight of body... 5. T.---f r-tt-= centrif. force. radius of circle of revolution X 32 velocity of revol. body" x weight of body, 6.-r, -- -= radius of centrifugal force X 32 the circle of revolution. _ centrif. force x 32 X rad. circle.., 7. 7 r. r; = weight of the re veloc of revolving body2 volving body. f/rad. circle x 32 X centrifugal force 8. " weight-'" Ve oC1 y' 9. There will be no difficulty in applying what has been said to practice. There are two fly-wheels of the same weight, one of which is 10 feet diameter, and makes 6 revolutions in a minute; what must the diameter of the other be to revolve 3 times in a minute 1 Here 6a: 3a:: 10: 2-5 = the diameter of the second. What is the centrifugal force of the rim of a fly-wheel, its diameter being 12 feet, and the weight of the rim 1 ton, making 65 turns in a minute? 2 X 3ft1f416 X 65 = 40-84 = 60 the velocity in feet per second; hence, the tendency to burst. Let us employ the centre of gyration.--If the fly above mentioned is in two halves, which are joined together by bolts capable of supporting 4 tons in all their positions, the whole weight of the wheel is lj tons, the circle of gyration is 5-5 feet from the axis of motion; what must be its velocity. so that its two halves may fly asunder? The force tending to separate the two halves will be j of the whole force; wherefore, by the rule, J32 X 4 X 2 = 30-636 = the velocity, . 11 X 3-1416 = 34-5576 = circumference of circle of gyration, wherefore, 34-5576: 30-636:: 60: 53-191 revolu tions in a minute. 10. The...show more

Product details

  • Paperback | 86 pages
  • 189 x 246 x 5mm | 168g
  • Rarebooksclub.com
  • Miami Fl, United States
  • English
  • black & white illustrations
  • 1236545907
  • 9781236545909