Descriptive Geometry for Students in Engineering Science and Architecture; A Carefully Graded Course of Instruction

By (author)

List price: US\$14.14

Currently unavailable

AbeBooks may have this title (opens in new window).

Description

This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1915 edition. Excerpt: ...V and H, these points, V and H, are in the traces of the bisecting planes required. The result is, that the line through H and e is the H.T., and from where this meets XY a line through v' is the V.T., of one of the required planes, while fH is the H.T., and a line through v' to meet fH in XY, is the V.T. of the other required plane. If, as is the case in this figure, there is not room enough to find the meeting of the H.T. and V.T. on XY for the last plane, then a point xx' should be chosen on the common intersection line, and a horizontal line on the required plane should be drawn to meet the V.P. at kk'. This latter point on the V.P. is in the V.T. required, which is obtained by joining v' to k'. If the H.T. of this last plane, marked fH, is parallel to XY, of course the V.T. of it, passing through v' will also be parallel to XY. Also, if the bisector P2f runs nearly parallel to H.T. 3, so that there is not room enough to find /, then the direction of the line fH may be obtained by making use of an inclined line in the plane required. EXERCISE XXV Find the traces of planes which bisect the dihedral angles contained by the pairs of planes It will now be seen, that, by supposing the rabattement of the angle between two planes, and working conversely to the method in Fig. 61, it will be possible to find the traces of a second plane at a given angle to a first one, whose traces may be given, and intersecting it in a line of given inclination to the H.P. For illustration, let the plane RST, Fig. 63, be given, and let it be required to find the traces of another which will cut into this one in a line of 300 to the H.P., and make a dihedral angle of, say, 700 with this given plane. From any point V in RS draw a line on the V.P. at 30 0 to XY. With v, ...