Chemical Calculations with Explanatory Notes, Problems, and Answers, Specially Adapted for Use in Colleges and Science Schools

Chemical Calculations with Explanatory Notes, Problems, and Answers, Specially Adapted for Use in Colleges and Science Schools

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This historic book may have numerous typos and missing text. Purchasers can download a free scanned copy of the original book (without typos) from the publisher. Not indexed. Not illustrated. 1896 edition. Excerpt: ...are required. Calculate the percentage of chlorine in the specimen. The equations representing the reactions are--KC103 + 3H, = KC1 + 3H20; KC1 + AgN03 = AgCl + KN03. Since the mol. wgt. of AgN03 = 170, a normal solution will contain 170 grams in 1 litre of solution;. 1 c.c. will contain 0-170 gram AgN03. If the solution is deci-normal, since only--of 170 J 10 grams is dissolved, 1 c.c. will equal 0-0170 gram AgN03. Now 170 grams AgN03 will precipitate 35-5 grams of chlorine as AgCl;.-. 1 c.c. of N AgN03 (= 0-17 gram) will precipitate (or is equivalent to) 0-0355 gram of chlorine; and.'. 1 c.c. of-AgN03 (= 0-017 gram) will precipitate (or is equivalent to) 0 00355 gram of chlorine. N In the example given, 26 c.c. of--AgN03 were used;, 26 x 0-00355 = the weight of 01, to which they are equivalent; and, since that is obtained from 0-32 gram KC103, the percentage amount is found by the following proportion: --0-32: 100:: 26x0-00355: x; 100 x26 x0-00355 oa a... x =----= 26-64: per cent, chlorine. L)-o-Z-Example 6.--100 c.c. of a solution of sulphurous acid re-N quired 5-15 c.c. of--iodine solution (1 c.c. = 0-0127 gm.) to completely oxidise it. Find the weight of SfX per litre of solution. S02 + I2 + 2H20 = H2S04 + 2HI. 1 To titrate a solution means to ascertain the titre, or strength, of it by volumetric methods. Since one molecule of iodine oxidises one molecule of sulphur dioxide; therefore--254 parts of iodine oxidise 64 parts of sulphur dioxide; now 100 c.c. of solution required 5-15 x 0-0127 gm. iodine;. lOOOc.c. require 51-5 x0-0127 and.-. 254: 51-5 x 0-0127:: 64: x, the S02 in solution. 51-5 x 0-0127 x 64 ntc-Aa nn--, x =---= 0 1648 gm. S02 in 1 litre. 254 Questions. 1. 1-2277 grams of crystallised copper...show more

Product details

  • Paperback | 26 pages
  • 189 x 246 x 1mm | 68g
  • Rarebooksclub.com
  • Miami Fl, United States
  • English
  • black & white illustrations
  • 1236538366
  • 9781236538369